Tommy, Lee and John had 300 coins. After Tommy used 13 coins and Lee used
37 of her coins, Tommy had four times as many coins left as Lee. John bought another 23 coins, he had twice the number of coins Lee had left. How many coins did John have at first?
| |
Tommy |
Lee |
John |
Total |
| Before |
16 u + 13 |
7 u |
8 u - 23 |
300 |
| Change |
- 13 |
- 3 u |
+ 23 |
|
| After |
16 u |
4 u |
8 u |
|
Comparing Tommy
and Lee in the end |
4 |
1 |
|
|
Comparing John
and Lee in the end |
|
1 |
2 |
|
Number of coins that Tommy had in the end
= 4 x 4 u
= 16 u
Number of coins that John had in the end
= 2 x 4 u
= 8 u
Total number of coins at first
= 16 u + 13 + 7 u + 8 u - 23
= 31 u - 10
31 u - 10 = 300
31 u = 300 + 10
31 u = 310
1 u = 310 ÷ 31 = 10
Number of coins that John had at first
= 8 u - 23
= 8 x 10 - 23
= 80 - 23
= 57
Answer(s): 57
