Pierre, Ahmad and Ryan had 189 stickers. After Pierre used 7 stickers and Ahmad used
14 of her stickers, Pierre had four times as many stickers left as Ahmad. Ryan bought another 16 stickers, he had twice the number of stickers Ahmad had left. How many stickers did Ryan have at first?
| |
Pierre |
Ahmad |
Ryan |
Total |
| Before |
12 u + 7 |
4 u |
6 u - 16 |
189 |
| Change |
- 7 |
- 1 u |
+ 16 |
|
| After |
12 u |
3 u |
6 u |
|
Comparing Pierre
and Ahmad in the end |
4 |
1 |
|
|
Comparing Ryan
and Ahmad in the end |
|
1 |
2 |
|
Number of stickers that Pierre had in the end
= 4 x 3 u
= 12 u
Number of stickers that Ryan had in the end
= 2 x 3 u
= 6 u
Total number of stickers at first
= 12 u + 7 + 4 u + 6 u - 16
= 22 u - 9
22 u - 9 = 189
22 u = 189 + 9
22 u = 198
1 u = 198 ÷ 22 = 9
Number of stickers that Ryan had at first
= 6 u - 16
= 6 x 9 - 16
= 54 - 16
= 38
Answer(s): 38
