Perry, Neave and Lee had 192 coins. After Perry used 13 coins and Neave used
15 of her coins, Perry had thrice as many coins left as Neave. Lee bought another 21 coins, he had twice the number of coins Neave had left. How many coins did Lee have at first?
| |
Perry |
Neave |
Lee |
Total |
| Before |
12 u + 13 |
5 u |
8 u - 21 |
192 |
| Change |
- 13 |
- 1 u |
+ 21 |
|
| After |
12 u |
4 u |
8 u |
|
Comparing Perry
and Neave in the end |
3 |
1 |
|
|
Comparing Lee
and Neave in the end |
|
1 |
2 |
|
Number of coins that Perry had in the end
= 3 x 4 u
= 12 u
Number of coins that Lee had in the end
= 2 x 4 u
= 8 u
Total number of coins at first
= 12 u + 13 + 5 u + 8 u - 21
= 25 u - 8
25 u - 8 = 192
25 u = 192 + 8
25 u = 200
1 u = 200 ÷ 25 = 8
Number of coins that Lee had at first
= 8 u - 21
= 8 x 8 - 21
= 64 - 21
= 43
Answer(s): 43
