Xavier, Charlie and Jenson had 133 coins. After Xavier used 18 coins and Charlie used
25 of her coins, Xavier had twice as many coins left as Charlie. Jenson bought another 25 coins, he had thrice the number of coins Charlie had left. How many coins did Jenson have at first?
| |
Xavier |
Charlie |
Jenson |
Total |
| Before |
6 u + 18 |
5 u |
9 u - 25 |
133 |
| Change |
- 18 |
- 2 u |
+ 25 |
|
| After |
6 u |
3 u |
9 u |
|
Comparing Xavier
and Charlie in the end |
2 |
1 |
|
|
Comparing Jenson
and Charlie in the end |
|
1 |
3 |
|
Number of coins that Xavier had in the end
= 2 x 3 u
= 6 u
Number of coins that Jenson had in the end
= 3 x 3 u
= 9 u
Total number of coins at first
= 6 u + 18 + 5 u + 9 u - 25
= 20 u - 7
20 u - 7 = 133
20 u = 133 + 7
20 u = 140
1 u = 140 ÷ 20 = 7
Number of coins that Jenson had at first
= 9 u - 25
= 9 x 7 - 25
= 63 - 25
= 38
Answer(s): 38
