Sean, Rael and Simon had 112 beads. After Sean used 13 beads and Rael used
13 of her beads, Sean had twice as many beads left as Rael. Simon bought another 21 beads, he had four times the number of beads Rael had left. How many beads did Simon have at first?
|
Sean |
Rael |
Simon |
Total |
Before |
4 u + 13 |
3 u |
8 u - 21 |
112 |
Change |
- 13 |
- 1 u |
+ 21 |
|
After |
4 u |
2 u |
8 u |
|
Comparing Sean and Rael in the end |
2 |
1 |
|
|
Comparing Simon and Rael in the end |
|
1 |
4 |
|
Number of beads that Sean had in the end
= 2 x 2 u
= 4 u
Number of beads that Simon had in the end
= 4 x 2 u
= 8 u
Total number of beads at first
= 4 u + 13 + 3 u + 8 u - 21
= 15 u - 8
15 u - 8 = 112
15 u = 112 + 8
15 u = 120
1 u = 120 ÷ 15 = 8
Number of beads that Simon had at first
= 8 u - 21
= 8 x 8 - 21
= 64 - 21
= 43
Answer(s): 43