One cafe bought 113 kg of beef and chicken.
12 of the beef and
57 of the chicken were sold. The amount of chicken sold was 20 kg more than the amount of beef sold.
- How much chicken did the cafe buy?
- How much beef did the cafe buy?
| |
Beef |
Chicken |
Total |
Before |
2x5 =
10 u |
7 u |
+ 28 |
113 |
Change |
- 1x5 =
- 5 u |
- 5 u |
- 20 |
|
After |
1x5 =
5 u |
2 u |
+ 8 |
|
(a)
20 ÷ 5 x 7 = 28
20 ÷ 5 x 2 = 8
Total mass of beef and chicken bought
= 10 u + 7 u + 28
= 17 u + 28
17 u + 28 = 113
17 u = 113 - 28
17 u = 85
1 u = 85 ÷ 17 = 5
Mass of chicken bought
= 7 u + 28
= 7 x 5 + 28
= 35 + 28
= 63 kg
(b)
Mass of beef bought
= 10 u
= 10 x 5
= 50 kg
Answer(s): (a) 63 kg; (b) 50 kg
