One restaurant bought 126 kg of chicken and pork.
13 of the chicken and
38 of the pork were sold. The amount of pork sold was 9 kg more than the amount of chicken sold.
- How much pork did the restaurant buy?
- How much chicken did the restaurant buy?
|
Chicken |
Pork |
Total |
Before |
3x3 = 9 u |
8 u |
+ 24 |
126 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 9 |
|
After |
2x3 = 6 u |
5 u |
+ 15 |
|
(a)
9 ÷ 3 x 8 = 24
9 ÷ 3 x 5 = 15
Total mass of chicken and pork bought
= 9 u + 8 u + 24
= 17 u + 24
17 u + 24 = 126
17 u = 126 - 24
17 u = 102
1 u = 102 ÷ 17 = 6
Mass of pork bought
= 8 u + 24
= 8 x 6 + 24
= 48 + 24
= 72 kg
(b)
Mass of chicken bought
= 9 u
= 9 x 6
= 54 kg
Answer(s): (a) 72 kg; (b) 54 kg