One cafe bought 92 kg of beef and pork.
15 of the beef and
34 of the pork were sold. The amount of pork sold was 12 kg more than the amount of beef sold.
- How much pork did the cafe buy?
- How much beef did the cafe buy?
| |
Beef |
Pork |
Total |
Before |
5x3 =
15 u |
4 u |
+ 16 |
92 |
Change |
- 1x3 =
- 3 u |
- 3 u |
- 12 |
|
After |
4x3 =
12 u |
1 u |
+ 4 |
|
(a)
12 ÷ 3 x 4 = 16
12 ÷ 3 x 1 = 4
Total mass of beef and pork bought
= 15 u + 4 u + 16
= 19 u + 16
19 u + 16 = 92
19 u = 92 - 16
19 u = 76
1 u = 76 ÷ 19 = 4
Mass of pork bought
= 4 u + 16
= 4 x 4 + 16
= 16 + 16
= 32 kg
(b)
Mass of beef bought
= 15 u
= 15 x 4
= 60 kg
Answer(s): (a) 32 kg; (b) 60 kg
