One restaurant bought 93 kg of beef and pork.
15 of the beef and
38 of the pork were sold. The amount of pork sold was 9 kg more than the amount of beef sold.
- How much pork did the restaurant buy?
- How much beef did the restaurant buy?
|
Beef |
Pork |
Total |
Before |
5x3 = 15 u |
8 u |
+ 24 |
93 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 9 |
|
After |
4x3 = 12 u |
5 u |
+ 15 |
|
(a)
9 ÷ 3 x 8 = 24
9 ÷ 3 x 5 = 15
Total mass of beef and pork bought
= 15 u + 8 u + 24
= 23 u + 24
23 u + 24 = 93
23 u = 93 - 24
23 u = 69
1 u = 69 ÷ 23 = 3
Mass of pork bought
= 8 u + 24
= 8 x 3 + 24
= 24 + 24
= 48 kg
(b)
Mass of beef bought
= 15 u
= 15 x 3
= 45 kg
Answer(s): (a) 48 kg; (b) 45 kg