One restaurant bought 163 kg of beef and mutton.
13 of the beef and
34 of the mutton were sold. The amount of mutton sold was 15 kg more than the amount of beef sold.
- How much mutton did the restaurant buy?
- How much beef did the restaurant buy?
|
Beef |
Mutton |
Total |
Before |
3x3 = 9 u |
4 u |
+ 20 |
163 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 15 |
|
After |
2x3 = 6 u |
1 u |
+ 5 |
|
(a)
15 ÷ 3 x 4 = 20
15 ÷ 3 x 1 = 5
Total mass of beef and mutton bought
= 9 u + 4 u + 20
= 13 u + 20
13 u + 20 = 163
13 u = 163 - 20
13 u = 143
1 u = 143 ÷ 13 = 11
Mass of mutton bought
= 4 u + 20
= 4 x 11 + 20
= 44 + 20
= 64 kg
(b)
Mass of beef bought
= 9 u
= 9 x 11
= 99 kg
Answer(s): (a) 64 kg; (b) 99 kg