One restaurant bought 49 kg of venison and mutton.
13 of the venison and
45 of the mutton were sold. The amount of mutton sold was 12 kg more than the amount of venison sold.
- How much mutton did the restaurant buy?
- How much venison did the restaurant buy?
|
Venison |
Mutton |
Total |
Before |
3x4 = 12 u |
5 u |
+ 15 |
49 |
Change |
- 1x4 = - 4 u |
- 4 u |
- 12 |
|
After |
2x4 = 8 u |
1 u |
+ 3 |
|
(a)
12 ÷ 4 x 5 = 15
12 ÷ 4 x 1 = 3
Total mass of venison and mutton bought
= 12 u + 5 u + 15
= 17 u + 15
17 u + 15 = 49
17 u = 49 - 15
17 u = 34
1 u = 34 ÷ 17 = 2
Mass of mutton bought
= 5 u + 15
= 5 x 2 + 15
= 10 + 15
= 25 kg
(b)
Mass of venison bought
= 12 u
= 12 x 2
= 24 kg
Answer(s): (a) 25 kg; (b) 24 kg