One restaurant bought 211 kg of chicken and pork.
15 of the chicken and
37 of the pork were sold. The amount of pork sold was 15 kg more than the amount of chicken sold.
- How much pork did the restaurant buy?
- How much chicken did the restaurant buy?
|
Chicken |
Pork |
Total |
Before |
5x3 = 15 u |
7 u |
+ 35 |
211 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 15 |
|
After |
4x3 = 12 u |
4 u |
+ 20 |
|
(a)
15 ÷ 3 x 7 = 35
15 ÷ 3 x 4 = 20
Total mass of chicken and pork bought
= 15 u + 7 u + 35
= 22 u + 35
22 u + 35 = 211
22 u = 211 - 35
22 u = 176
1 u = 176 ÷ 22 = 8
Mass of pork bought
= 7 u + 35
= 7 x 8 + 35
= 56 + 35
= 91 kg
(b)
Mass of chicken bought
= 15 u
= 15 x 8
= 120 kg
Answer(s): (a) 91 kg; (b) 120 kg