One eatery bought 106 kg of mutton and venison.
12 of the mutton and
25 of the venison were sold. The amount of venison sold was 10 kg more than the amount of mutton sold.
- How much venison did the eatery buy?
- How much mutton did the eatery buy?
|
Mutton |
Venison |
Total |
Before |
2x2 = 4 u |
5 u |
+ 25 |
106 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 10 |
|
After |
1x2 = 2 u |
3 u |
+ 15 |
|
(a)
10 ÷ 2 x 5 = 25
10 ÷ 2 x 3 = 15
Total mass of mutton and venison bought
= 4 u + 5 u + 25
= 9 u + 25
9 u + 25 = 106
9 u = 106 - 25
9 u = 81
1 u = 81 ÷ 9 = 9
Mass of venison bought
= 5 u + 25
= 5 x 9 + 25
= 45 + 25
= 70 kg
(b)
Mass of mutton bought
= 4 u
= 4 x 9
= 36 kg
Answer(s): (a) 70 kg; (b) 36 kg