One eating house bought 118 kg of mutton and venison.
12 of the mutton and
25 of the venison were sold. The amount of venison sold was 4 kg more than the amount of mutton sold.
- How much venison did the eating house buy?
- How much mutton did the eating house buy?
|
Mutton |
Venison |
Total |
Before |
2x2 = 4 u |
5 u |
+ 10 |
118 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 4 |
|
After |
1x2 = 2 u |
3 u |
+ 6 |
|
(a)
4 ÷ 2 x 5 = 10
4 ÷ 2 x 3 = 6
Total mass of mutton and venison bought
= 4 u + 5 u + 10
= 9 u + 10
9 u + 10 = 118
9 u = 118 - 10
9 u = 108
1 u = 108 ÷ 9 = 12
Mass of venison bought
= 5 u + 10
= 5 x 12 + 10
= 60 + 10
= 70 kg
(b)
Mass of mutton bought
= 4 u
= 4 x 12
= 48 kg
Answer(s): (a) 70 kg; (b) 48 kg