One cafe bought 125 kg of mutton and beef.
14 of the mutton and
27 of the beef were sold. The amount of beef sold was 10 kg more than the amount of mutton sold.
- How much beef did the cafe buy?
- How much mutton did the cafe buy?
| |
Mutton |
Beef |
Total |
Before |
4x2 =
8 u |
7 u |
+ 35 |
125 |
Change |
- 1x2 =
- 2 u |
- 2 u |
- 10 |
|
After |
3x2 =
6 u |
5 u |
+ 25 |
|
(a)
10 ÷ 2 x 7 = 35
10 ÷ 2 x 5 = 25
Total mass of mutton and beef bought
= 8 u + 7 u + 35
= 15 u + 35
15 u + 35 = 125
15 u = 125 - 35
15 u = 90
1 u = 90 ÷ 15 = 6
Mass of beef bought
= 7 u + 35
= 7 x 6 + 35
= 42 + 35
= 77 kg
(b)
Mass of mutton bought
= 8 u
= 8 x 6
= 48 kg
Answer(s): (a) 77 kg; (b) 48 kg
