One eatery bought 225 kg of venison and pork.
15 of the venison and
45 of the pork were sold. The amount of pork sold was 20 kg more than the amount of venison sold.
- How much pork did the eatery buy?
- How much venison did the eatery buy?
| |
Venison |
Pork |
Total |
Before |
5x4 =
20 u |
5 u |
+ 25 |
225 |
Change |
- 1x4 =
- 4 u |
- 4 u |
- 20 |
|
After |
4x4 =
16 u |
1 u |
+ 5 |
|
(a)
20 ÷ 4 x 5 = 25
20 ÷ 4 x 1 = 5
Total mass of venison and pork bought
= 20 u + 5 u + 25
= 25 u + 25
25 u + 25 = 225
25 u = 225 - 25
25 u = 200
1 u = 200 ÷ 25 = 8
Mass of pork bought
= 5 u + 25
= 5 x 8 + 25
= 40 + 25
= 65 kg
(b)
Mass of venison bought
= 20 u
= 20 x 8
= 160 kg
Answer(s): (a) 65 kg; (b) 160 kg
