One eatery bought 101 kg of pork and chicken.
13 of the pork and
38 of the chicken were sold. The amount of chicken sold was 6 kg more than the amount of pork sold.
- How much chicken did the eatery buy?
- How much pork did the eatery buy?
|
Pork |
Chicken |
Total |
Before |
3x3 = 9 u |
8 u |
+ 16 |
101 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 6 |
|
After |
2x3 = 6 u |
5 u |
+ 10 |
|
(a)
6 ÷ 3 x 8 = 16
6 ÷ 3 x 5 = 10
Total mass of pork and chicken bought
= 9 u + 8 u + 16
= 17 u + 16
17 u + 16 = 101
17 u = 101 - 16
17 u = 85
1 u = 85 ÷ 17 = 5
Mass of chicken bought
= 8 u + 16
= 8 x 5 + 16
= 40 + 16
= 56 kg
(b)
Mass of pork bought
= 9 u
= 9 x 5
= 45 kg
Answer(s): (a) 56 kg; (b) 45 kg