One canteen bought 130 kg of mutton and beef.
13 of the mutton and
47 of the beef were sold. The amount of beef sold was 20 kg more than the amount of mutton sold.
- How much beef did the canteen buy?
- How much mutton did the canteen buy?
|
Mutton |
Beef |
Total |
Before |
3x4 = 12 u |
7 u |
+ 35 |
130 |
Change |
- 1x4 = - 4 u |
- 4 u |
- 20 |
|
After |
2x4 = 8 u |
3 u |
+ 15 |
|
(a)
20 ÷ 4 x 7 = 35
20 ÷ 4 x 3 = 15
Total mass of mutton and beef bought
= 12 u + 7 u + 35
= 19 u + 35
19 u + 35 = 130
19 u = 130 - 35
19 u = 95
1 u = 95 ÷ 19 = 5
Mass of beef bought
= 7 u + 35
= 7 x 5 + 35
= 35 + 35
= 70 kg
(b)
Mass of mutton bought
= 12 u
= 12 x 5
= 60 kg
Answer(s): (a) 70 kg; (b) 60 kg