One restaurant bought 211 kg of chicken and venison.
13 of the chicken and
47 of the venison were sold. The amount of venison sold was 12 kg more than the amount of chicken sold.
- How much venison did the restaurant buy?
- How much chicken did the restaurant buy?
|
Chicken |
Venison |
Total |
Before |
3x4 = 12 u |
7 u |
+ 21 |
211 |
Change |
- 1x4 = - 4 u |
- 4 u |
- 12 |
|
After |
2x4 = 8 u |
3 u |
+ 9 |
|
(a)
12 ÷ 4 x 7 = 21
12 ÷ 4 x 3 = 9
Total mass of chicken and venison bought
= 12 u + 7 u + 21
= 19 u + 21
19 u + 21 = 211
19 u = 211 - 21
19 u = 190
1 u = 190 ÷ 19 = 10
Mass of venison bought
= 7 u + 21
= 7 x 10 + 21
= 70 + 21
= 91 kg
(b)
Mass of chicken bought
= 12 u
= 12 x 10
= 120 kg
Answer(s): (a) 91 kg; (b) 120 kg