One restaurant bought 76 kg of mutton and venison.
12 of the mutton and
35 of the venison were sold. The amount of venison sold was 6 kg more than the amount of mutton sold.
- How much venison did the restaurant buy?
- How much mutton did the restaurant buy?
|
Mutton |
Venison |
Total |
Before |
2x3 = 6 u |
5 u |
+ 10 |
76 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 6 |
|
After |
1x3 = 3 u |
2 u |
+ 4 |
|
(a)
6 ÷ 3 x 5 = 10
6 ÷ 3 x 2 = 4
Total mass of mutton and venison bought
= 6 u + 5 u + 10
= 11 u + 10
11 u + 10 = 76
11 u = 76 - 10
11 u = 66
1 u = 66 ÷ 11 = 6
Mass of venison bought
= 5 u + 10
= 5 x 6 + 10
= 30 + 10
= 40 kg
(b)
Mass of mutton bought
= 6 u
= 6 x 6
= 36 kg
Answer(s): (a) 40 kg; (b) 36 kg