One restaurant bought 119 kg of beef and mutton.
12 of the beef and
35 of the mutton were sold. The amount of mutton sold was 12 kg more than the amount of beef sold.
- How much mutton did the restaurant buy?
- How much beef did the restaurant buy?
|
Beef |
Mutton |
Total |
Before |
2x3 = 6 u |
5 u |
+ 20 |
119 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 12 |
|
After |
1x3 = 3 u |
2 u |
+ 8 |
|
(a)
12 ÷ 3 x 5 = 20
12 ÷ 3 x 2 = 8
Total mass of beef and mutton bought
= 6 u + 5 u + 20
= 11 u + 20
11 u + 20 = 119
11 u = 119 - 20
11 u = 99
1 u = 99 ÷ 11 = 9
Mass of mutton bought
= 5 u + 20
= 5 x 9 + 20
= 45 + 20
= 65 kg
(b)
Mass of beef bought
= 6 u
= 6 x 9
= 54 kg
Answer(s): (a) 65 kg; (b) 54 kg