One eating house bought 102 kg of venison and mutton.
13 of the venison and
25 of the mutton were sold. The amount of mutton sold was 10 kg more than the amount of venison sold.
- How much mutton did the eating house buy?
- How much venison did the eating house buy?
|
Venison |
Mutton |
Total |
Before |
3x2 = 6 u |
5 u |
+ 25 |
102 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 10 |
|
After |
2x2 = 4 u |
3 u |
+ 15 |
|
(a)
10 ÷ 2 x 5 = 25
10 ÷ 2 x 3 = 15
Total mass of venison and mutton bought
= 6 u + 5 u + 25
= 11 u + 25
11 u + 25 = 102
11 u = 102 - 25
11 u = 77
1 u = 77 ÷ 11 = 7
Mass of mutton bought
= 5 u + 25
= 5 x 7 + 25
= 35 + 25
= 60 kg
(b)
Mass of venison bought
= 6 u
= 6 x 7
= 42 kg
Answer(s): (a) 60 kg; (b) 42 kg