One eatery bought 318 kg of chicken and mutton.
14 of the chicken and
57 of the mutton were sold. The amount of mutton sold was 15 kg more than the amount of chicken sold.
- How much mutton did the eatery buy?
- How much chicken did the eatery buy?
|
Chicken |
Mutton |
Total |
Before |
4x5 = 20 u |
7 u |
+ 21 |
318 |
Change |
- 1x5 = - 5 u |
- 5 u |
- 15 |
|
After |
3x5 = 15 u |
2 u |
+ 6 |
|
(a)
15 ÷ 5 x 7 = 21
15 ÷ 5 x 2 = 6
Total mass of chicken and mutton bought
= 20 u + 7 u + 21
= 27 u + 21
27 u + 21 = 318
27 u = 318 - 21
27 u = 297
1 u = 297 ÷ 27 = 11
Mass of mutton bought
= 7 u + 21
= 7 x 11 + 21
= 77 + 21
= 98 kg
(b)
Mass of chicken bought
= 20 u
= 20 x 11
= 220 kg
Answer(s): (a) 98 kg; (b) 220 kg