One restaurant bought 304 kg of pork and venison.
15 of the pork and
58 of the venison were sold. The amount of venison sold was 25 kg more than the amount of pork sold.
- How much venison did the restaurant buy?
- How much pork did the restaurant buy?
|
Pork |
Venison |
Total |
Before |
5x5 = 25 u |
8 u |
+ 40 |
304 |
Change |
- 1x5 = - 5 u |
- 5 u |
- 25 |
|
After |
4x5 = 20 u |
3 u |
+ 15 |
|
(a)
25 ÷ 5 x 8 = 40
25 ÷ 5 x 3 = 15
Total mass of pork and venison bought
= 25 u + 8 u + 40
= 33 u + 40
33 u + 40 = 304
33 u = 304 - 40
33 u = 264
1 u = 264 ÷ 33 = 8
Mass of venison bought
= 8 u + 40
= 8 x 8 + 40
= 64 + 40
= 104 kg
(b)
Mass of pork bought
= 25 u
= 25 x 8
= 200 kg
Answer(s): (a) 104 kg; (b) 200 kg