One food outlet bought 188 kg of beef and pork.
13 of the beef and
37 of the pork were sold. The amount of pork sold was 12 kg more than the amount of beef sold.
- How much pork did the food outlet buy?
- How much beef did the food outlet buy?
|
Beef |
Pork |
Total |
Before |
3x3 = 9 u |
7 u |
+ 28 |
188 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 12 |
|
After |
2x3 = 6 u |
4 u |
+ 16 |
|
(a)
12 ÷ 3 x 7 = 28
12 ÷ 3 x 4 = 16
Total mass of beef and pork bought
= 9 u + 7 u + 28
= 16 u + 28
16 u + 28 = 188
16 u = 188 - 28
16 u = 160
1 u = 160 ÷ 16 = 10
Mass of pork bought
= 7 u + 28
= 7 x 10 + 28
= 70 + 28
= 98 kg
(b)
Mass of beef bought
= 9 u
= 9 x 10
= 90 kg
Answer(s): (a) 98 kg; (b) 90 kg