One restaurant bought 132 kg of venison and beef.
14 of the venison and
38 of the beef were sold. The amount of beef sold was 12 kg more than the amount of venison sold.
- How much beef did the restaurant buy?
- How much venison did the restaurant buy?
|
Venison |
Beef |
Total |
Before |
4x3 = 12 u |
8 u |
+ 32 |
132 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 12 |
|
After |
3x3 = 9 u |
5 u |
+ 20 |
|
(a)
12 ÷ 3 x 8 = 32
12 ÷ 3 x 5 = 20
Total mass of venison and beef bought
= 12 u + 8 u + 32
= 20 u + 32
20 u + 32 = 132
20 u = 132 - 32
20 u = 100
1 u = 100 ÷ 20 = 5
Mass of beef bought
= 8 u + 32
= 8 x 5 + 32
= 40 + 32
= 72 kg
(b)
Mass of venison bought
= 12 u
= 12 x 5
= 60 kg
Answer(s): (a) 72 kg; (b) 60 kg