One eating house bought 97 kg of beef and pork.
13 of the beef and
25 of the pork were sold. The amount of pork sold was 8 kg more than the amount of beef sold.
- How much pork did the eating house buy?
- How much beef did the eating house buy?
|
Beef |
Pork |
Total |
Before |
3x2 = 6 u |
5 u |
+ 20 |
97 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 8 |
|
After |
2x2 = 4 u |
3 u |
+ 12 |
|
(a)
8 ÷ 2 x 5 = 20
8 ÷ 2 x 3 = 12
Total mass of beef and pork bought
= 6 u + 5 u + 20
= 11 u + 20
11 u + 20 = 97
11 u = 97 - 20
11 u = 77
1 u = 77 ÷ 11 = 7
Mass of pork bought
= 5 u + 20
= 5 x 7 + 20
= 35 + 20
= 55 kg
(b)
Mass of beef bought
= 6 u
= 6 x 7
= 42 kg
Answer(s): (a) 55 kg; (b) 42 kg