One cafe bought 93 kg of chicken and beef.
12 of the chicken and
45 of the beef were sold. The amount of beef sold was 12 kg more than the amount of chicken sold.
- How much beef did the cafe buy?
- How much chicken did the cafe buy?
|
Chicken |
Beef |
Total |
Before |
2x4 = 8 u |
5 u |
+ 15 |
93 |
Change |
- 1x4 = - 4 u |
- 4 u |
- 12 |
|
After |
1x4 = 4 u |
1 u |
+ 3 |
|
(a)
12 ÷ 4 x 5 = 15
12 ÷ 4 x 1 = 3
Total mass of chicken and beef bought
= 8 u + 5 u + 15
= 13 u + 15
13 u + 15 = 93
13 u = 93 - 15
13 u = 78
1 u = 78 ÷ 13 = 6
Mass of beef bought
= 5 u + 15
= 5 x 6 + 15
= 30 + 15
= 45 kg
(b)
Mass of chicken bought
= 8 u
= 8 x 6
= 48 kg
Answer(s): (a) 45 kg; (b) 48 kg