One eating house bought 170 kg of venison and mutton.
12 of the venison and
38 of the mutton were sold. The amount of mutton sold was 6 kg more than the amount of venison sold.
- How much mutton did the eating house buy?
- How much venison did the eating house buy?
|
Venison |
Mutton |
Total |
Before |
2x3 = 6 u |
8 u |
+ 16 |
170 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 6 |
|
After |
1x3 = 3 u |
5 u |
+ 10 |
|
(a)
6 ÷ 3 x 8 = 16
6 ÷ 3 x 5 = 10
Total mass of venison and mutton bought
= 6 u + 8 u + 16
= 14 u + 16
14 u + 16 = 170
14 u = 170 - 16
14 u = 154
1 u = 154 ÷ 14 = 11
Mass of mutton bought
= 8 u + 16
= 8 x 11 + 16
= 88 + 16
= 104 kg
(b)
Mass of venison bought
= 6 u
= 6 x 11
= 66 kg
Answer(s): (a) 104 kg; (b) 66 kg