One coffee shop bought 203 kg of mutton and beef.
14 of the mutton and
57 of the beef were sold. The amount of beef sold was 10 kg more than the amount of mutton sold.
- How much beef did the coffee shop buy?
- How much mutton did the coffee shop buy?
|
Mutton |
Beef |
Total |
Before |
4x5 = 20 u |
7 u |
+ 14 |
203 |
Change |
- 1x5 = - 5 u |
- 5 u |
- 10 |
|
After |
3x5 = 15 u |
2 u |
+ 4 |
|
(a)
10 ÷ 5 x 7 = 14
10 ÷ 5 x 2 = 4
Total mass of mutton and beef bought
= 20 u + 7 u + 14
= 27 u + 14
27 u + 14 = 203
27 u = 203 - 14
27 u = 189
1 u = 189 ÷ 27 = 7
Mass of beef bought
= 7 u + 14
= 7 x 7 + 14
= 49 + 14
= 63 kg
(b)
Mass of mutton bought
= 20 u
= 20 x 7
= 140 kg
Answer(s): (a) 63 kg; (b) 140 kg