One eatery bought 163 kg of beef and pork.
13 of the beef and
37 of the pork were sold. The amount of pork sold was 15 kg more than the amount of beef sold.
- How much pork did the eatery buy?
- How much beef did the eatery buy?
|
Beef |
Pork |
Total |
Before |
3x3 = 9 u |
7 u |
+ 35 |
163 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 15 |
|
After |
2x3 = 6 u |
4 u |
+ 20 |
|
(a)
15 ÷ 3 x 7 = 35
15 ÷ 3 x 4 = 20
Total mass of beef and pork bought
= 9 u + 7 u + 35
= 16 u + 35
16 u + 35 = 163
16 u = 163 - 35
16 u = 128
1 u = 128 ÷ 16 = 8
Mass of pork bought
= 7 u + 35
= 7 x 8 + 35
= 56 + 35
= 91 kg
(b)
Mass of beef bought
= 9 u
= 9 x 8
= 72 kg
Answer(s): (a) 91 kg; (b) 72 kg