One cafe bought 160 kg of beef and chicken.
15 of the beef and
34 of the chicken were sold. The amount of chicken sold was 6 kg more than the amount of beef sold.
- How much chicken did the cafe buy?
- How much beef did the cafe buy?
|
Beef |
Chicken |
Total |
Before |
5x3 = 15 u |
4 u |
+ 8 |
160 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 6 |
|
After |
4x3 = 12 u |
1 u |
+ 2 |
|
(a)
6 ÷ 3 x 4 = 8
6 ÷ 3 x 1 = 2
Total mass of beef and chicken bought
= 15 u + 4 u + 8
= 19 u + 8
19 u + 8 = 160
19 u = 160 - 8
19 u = 152
1 u = 152 ÷ 19 = 8
Mass of chicken bought
= 4 u + 8
= 4 x 8 + 8
= 32 + 8
= 40 kg
(b)
Mass of beef bought
= 15 u
= 15 x 8
= 120 kg
Answer(s): (a) 40 kg; (b) 120 kg