One cafe bought 305 kg of mutton and pork.
15 of the mutton and
47 of the pork were sold. The amount of pork sold was 20 kg more than the amount of mutton sold.
- How much pork did the cafe buy?
- How much mutton did the cafe buy?
| |
Mutton |
Pork |
Total |
Before |
5x4 =
20 u |
7 u |
+ 35 |
305 |
Change |
- 1x4 =
- 4 u |
- 4 u |
- 20 |
|
After |
4x4 =
16 u |
3 u |
+ 15 |
|
(a)
20 ÷ 4 x 7 = 35
20 ÷ 4 x 3 = 15
Total mass of mutton and pork bought
= 20 u + 7 u + 35
= 27 u + 35
27 u + 35 = 305
27 u = 305 - 35
27 u = 270
1 u = 270 ÷ 27 = 10
Mass of pork bought
= 7 u + 35
= 7 x 10 + 35
= 70 + 35
= 105 kg
(b)
Mass of mutton bought
= 20 u
= 20 x 10
= 200 kg
Answer(s): (a) 105 kg; (b) 200 kg
