One coffee shop bought 90 kg of mutton and beef.
14 of the mutton and
37 of the beef were sold. The amount of beef sold was 6 kg more than the amount of mutton sold.
- How much beef did the coffee shop buy?
- How much mutton did the coffee shop buy?
|
Mutton |
Beef |
Total |
Before |
4x3 = 12 u |
7 u |
+ 14 |
90 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 6 |
|
After |
3x3 = 9 u |
4 u |
+ 8 |
|
(a)
6 ÷ 3 x 7 = 14
6 ÷ 3 x 4 = 8
Total mass of mutton and beef bought
= 12 u + 7 u + 14
= 19 u + 14
19 u + 14 = 90
19 u = 90 - 14
19 u = 76
1 u = 76 ÷ 19 = 4
Mass of beef bought
= 7 u + 14
= 7 x 4 + 14
= 28 + 14
= 42 kg
(b)
Mass of mutton bought
= 12 u
= 12 x 4
= 48 kg
Answer(s): (a) 42 kg; (b) 48 kg