One restaurant bought 412 kg of venison and pork.
15 of the venison and
58 of the pork were sold. The amount of pork sold was 10 kg more than the amount of venison sold.
- How much pork did the restaurant buy?
- How much venison did the restaurant buy?
|
Venison |
Pork |
Total |
Before |
5x5 = 25 u |
8 u |
+ 16 |
412 |
Change |
- 1x5 = - 5 u |
- 5 u |
- 10 |
|
After |
4x5 = 20 u |
3 u |
+ 6 |
|
(a)
10 ÷ 5 x 8 = 16
10 ÷ 5 x 3 = 6
Total mass of venison and pork bought
= 25 u + 8 u + 16
= 33 u + 16
33 u + 16 = 412
33 u = 412 - 16
33 u = 396
1 u = 396 ÷ 33 = 12
Mass of pork bought
= 8 u + 16
= 8 x 12 + 16
= 96 + 16
= 112 kg
(b)
Mass of venison bought
= 25 u
= 25 x 12
= 300 kg
Answer(s): (a) 112 kg; (b) 300 kg