One coffee shop bought 168 kg of beef and mutton.
15 of the beef and
34 of the mutton were sold. The amount of mutton sold was 12 kg more than the amount of beef sold.
- How much mutton did the coffee shop buy?
- How much beef did the coffee shop buy?
|
Beef |
Mutton |
Total |
Before |
5x3 = 15 u |
4 u |
+ 16 |
168 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 12 |
|
After |
4x3 = 12 u |
1 u |
+ 4 |
|
(a)
12 ÷ 3 x 4 = 16
12 ÷ 3 x 1 = 4
Total mass of beef and mutton bought
= 15 u + 4 u + 16
= 19 u + 16
19 u + 16 = 168
19 u = 168 - 16
19 u = 152
1 u = 152 ÷ 19 = 8
Mass of mutton bought
= 4 u + 16
= 4 x 8 + 16
= 32 + 16
= 48 kg
(b)
Mass of beef bought
= 15 u
= 15 x 8
= 120 kg
Answer(s): (a) 48 kg; (b) 120 kg