One cafe bought 104 kg of pork and chicken.
13 of the pork and
47 of the chicken were sold. The amount of chicken sold was 16 kg more than the amount of pork sold.
- How much chicken did the cafe buy?
- How much pork did the cafe buy?
| |
Pork |
Chicken |
Total |
Before |
3x4 =
12 u |
7 u |
+ 28 |
104 |
Change |
- 1x4 =
- 4 u |
- 4 u |
- 16 |
|
After |
2x4 =
8 u |
3 u |
+ 12 |
|
(a)
16 ÷ 4 x 7 = 28
16 ÷ 4 x 3 = 12
Total mass of pork and chicken bought
= 12 u + 7 u + 28
= 19 u + 28
19 u + 28 = 104
19 u = 104 - 28
19 u = 76
1 u = 76 ÷ 19 = 4
Mass of chicken bought
= 7 u + 28
= 7 x 4 + 28
= 28 + 28
= 56 kg
(b)
Mass of pork bought
= 12 u
= 12 x 4
= 48 kg
Answer(s): (a) 56 kg; (b) 48 kg
