One eatery bought 88 kg of pork and mutton.
14 of the pork and
27 of the mutton were sold. The amount of mutton sold was 8 kg more than the amount of pork sold.
- How much mutton did the eatery buy?
- How much pork did the eatery buy?
|
Pork |
Mutton |
Total |
Before |
4x2 = 8 u |
7 u |
+ 28 |
88 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 8 |
|
After |
3x2 = 6 u |
5 u |
+ 20 |
|
(a)
8 ÷ 2 x 7 = 28
8 ÷ 2 x 5 = 20
Total mass of pork and mutton bought
= 8 u + 7 u + 28
= 15 u + 28
15 u + 28 = 88
15 u = 88 - 28
15 u = 60
1 u = 60 ÷ 15 = 4
Mass of mutton bought
= 7 u + 28
= 7 x 4 + 28
= 28 + 28
= 56 kg
(b)
Mass of pork bought
= 8 u
= 8 x 4
= 32 kg
Answer(s): (a) 56 kg; (b) 32 kg