One coffee shop bought 130 kg of pork and venison.
13 of the pork and
25 of the venison were sold. The amount of venison sold was 8 kg more than the amount of pork sold.
- How much venison did the coffee shop buy?
- How much pork did the coffee shop buy?
|
Pork |
Venison |
Total |
Before |
3x2 = 6 u |
5 u |
+ 20 |
130 |
Change |
- 1x2 = - 2 u |
- 2 u |
- 8 |
|
After |
2x2 = 4 u |
3 u |
+ 12 |
|
(a)
8 ÷ 2 x 5 = 20
8 ÷ 2 x 3 = 12
Total mass of pork and venison bought
= 6 u + 5 u + 20
= 11 u + 20
11 u + 20 = 130
11 u = 130 - 20
11 u = 110
1 u = 110 ÷ 11 = 10
Mass of venison bought
= 5 u + 20
= 5 x 10 + 20
= 50 + 20
= 70 kg
(b)
Mass of pork bought
= 6 u
= 6 x 10
= 60 kg
Answer(s): (a) 70 kg; (b) 60 kg