Luke, Oliver and Seth bought some biscuits. After Luke ate ³₈ of his biscuits, Oliver ate ²₃ of his biscuits and Seth ate 10 biscuits, each of them had the same number of biscuits left. Luke had 14 less biscuits than Oliver at first.

1. How many biscuits did Luke have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Luke	Oliver	Seth
Before	8 u	3x5 = 15 u	5 u + 10
Change	- 3 u	- 2x5 = - 10 u	- 10
After	5 u	1x5 = 5 u	5 u

(a)
The number of biscuits that Luke and Oliver each had in the end is the same. Make the number of biscuits that Luke and Oliver each had in the end the same.  LCM of 5 and 1 is 5.

Number of biscuits that Luke had less than Oliver at first
= 15 u - 8 u
= 7 u

7 u = 14

1 u = 14 ÷ 7 = 2

Number of biscuits that Luke had at first
= 8 u
= 8 x 2
= 16 

(b)
Total number of biscuits that the 3 of them bought
= 8 u + 15 u + 5 u + 10
= 28 u + 10
= 28 x 2 + 10
= 56 + 10
= 66

Answer(s): (a) 16; (b) 66