Warren, Asher and David bought some wafers. After Warren ate ³₇ of his wafers, Asher ate ²₃ of his wafers and David ate 4 wafers, each of them had the same number of wafers left. Warren had 50 less wafers than Asher at first.

1. How many wafers did Warren have at first?
2. How many wafers did the 3 of them buy altogether? 

	Warren	Asher	David
Before	7 u	3x4 = 12 u	4 u + 4
Change	- 3 u	- 2x4 = - 8 u	- 4
After	4 u	1x4 = 4 u	4 u

(a)
The number of wafers that Warren and Asher each had in the end is the same. Make the number of wafers that Warren and Asher each had in the end the same.  LCM of 4 and 1 is 4.

Number of wafers that Warren had less than Asher at first
= 12 u - 7 u
= 5 u

5 u = 50

1 u = 50 ÷ 5 = 10

Number of wafers that Warren had at first
= 7 u
= 7 x 10
= 70 

(b)
Total number of wafers that the 3 of them bought
= 7 u + 12 u + 4 u + 4
= 23 u + 4
= 23 x 10 + 4
= 230 + 4
= 234

Answer(s): (a) 70; (b) 234