Julian, Reggie and Albert bought some muffins. After Julian ate ⁴₇ of his muffins, Reggie ate ⁴₅ of his muffins and Albert ate 11 muffins, each of them had the same number of muffins left. Julian had 56 less muffins than Reggie at first.

1. How many muffins did Julian have at first?
2. How many muffins did the 3 of them buy altogether? 

	Julian	Reggie	Albert
Before	7 u	5x3 = 15 u	3 u + 11
Change	- 4 u	- 4x3 = - 12 u	- 11
After	3 u	1x3 = 3 u	3 u

(a)
The number of muffins that Julian and Reggie each had in the end is the same. Make the number of muffins that Julian and Reggie each had in the end the same.  LCM of 3 and 1 is 3.

Number of muffins that Julian had less than Reggie at first
= 15 u - 7 u
= 8 u

8 u = 56

1 u = 56 ÷ 8 = 7

Number of muffins that Julian had at first
= 7 u
= 7 x 7
= 49 

(b)
Total number of muffins that the 3 of them bought
= 7 u + 15 u + 3 u + 11
= 25 u + 11
= 25 x 7 + 11
= 175 + 11
= 186

Answer(s): (a) 49; (b) 186