Fred, Ben and Dylan bought some wafers. After Fred ate
58 of his wafers, Ben ate
34 of his wafers and Dylan ate 8 wafers, each of them had the same number of wafers left. Fred had 24 less wafers than Ben at first.
- How many wafers did Fred have at first?
- How many wafers did the 3 of them buy altogether?
| |
Fred |
Ben |
Dylan |
Before |
8 u |
4x3 =
12 u |
3 u + 8 |
Change |
- 5 u |
- 3x3 =
- 9 u |
- 8 |
After |
3 u |
1x3 =
3 u |
3 u |
(a)
The number of wafers that Fred and Ben each had in the end is the same. Make the number of wafers that Fred and Ben each had in the end the same. LCM of 3 and 1 is 3.
Number of wafers that Fred had less than Ben at first
= 12 u - 8 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of wafers that Fred had at first
= 8 u
= 8 x 6
= 48
(b)
Total number of wafers that the 3 of them bought
= 8 u + 12 u + 3 u + 8
= 23 u + 8
= 23 x 6 + 8
= 138 + 8
= 146
Answer(s): (a) 48; (b) 146
