Daniel, Fred and Ivan bought some croissants. After Daniel ate ³₅ of his croissants, Fred ate ³₄ of his croissants and Ivan ate 7 croissants, each of them had the same number of croissants left. Daniel had 18 less croissants than Fred at first.

1. How many croissants did Daniel have at first?
2. How many croissants did the 3 of them buy altogether? 

	Daniel	Fred	Ivan
Before	5 u	4x2 = 8 u	2 u + 7
Change	- 3 u	- 3x2 = - 6 u	- 7
After	2 u	1x2 = 2 u	2 u

(a)
The number of croissants that Daniel and Fred each had in the end is the same. Make the number of croissants that Daniel and Fred each had in the end the same.  LCM of 2 and 1 is 2.

Number of croissants that Daniel had less than Fred at first
= 8 u - 5 u
= 3 u

3 u = 18

1 u = 18 ÷ 3 = 6

Number of croissants that Daniel had at first
= 5 u
= 5 x 6
= 30 

(b)
Total number of croissants that the 3 of them bought
= 5 u + 8 u + 2 u + 7
= 15 u + 7
= 15 x 6 + 7
= 90 + 7
= 97

Answer(s): (a) 30; (b) 97