Bobby, Oscar and Harry bought some wafers. After Bobby ate ⁵₇ of his wafers, Oscar ate ²₃ of his wafers and Harry ate 6 wafers, each of them had the same number of wafers left. Bobby had -8 less wafers than Oscar at first.

1. How many wafers did Bobby have at first?
2. How many wafers did the 3 of them buy altogether? 

	Bobby	Oscar	Harry
Before	7 u	3x2 = 6 u	2 u + 6
Change	- 5 u	- 2x2 = - 4 u	- 6
After	2 u	1x2 = 2 u	2 u

(a)
The number of wafers that Bobby and Oscar each had in the end is the same. Make the number of wafers that Bobby and Oscar each had in the end the same.  LCM of 2 and 1 is 2.

Number of wafers that Bobby had less than Oscar at first
= 6 u - 7 u
= -1 u

-1 u = -8

1 u = -8 ÷ -1 = 8

Number of wafers that Bobby had at first
= 7 u
= 7 x 8
= 56 

(b)
Total number of wafers that the 3 of them bought
= 7 u + 6 u + 2 u + 6
= 15 u + 6
= 15 x 8 + 6
= 120 + 6
= 126

Answer(s): (a) 56; (b) 126