Jenson, Valen and Michael bought some biscuits. After Jenson ate ³₈ of his biscuits, Valen ate ²₃ of his biscuits and Michael ate 2 biscuits, each of them had the same number of biscuits left. Jenson had 70 less biscuits than Valen at first.

1. How many biscuits did Jenson have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Jenson	Valen	Michael
Before	8 u	3x5 = 15 u	5 u + 2
Change	- 3 u	- 2x5 = - 10 u	- 2
After	5 u	1x5 = 5 u	5 u

(a)
The number of biscuits that Jenson and Valen each had in the end is the same. Make the number of biscuits that Jenson and Valen each had in the end the same.  LCM of 5 and 1 is 5.

Number of biscuits that Jenson had less than Valen at first
= 15 u - 8 u
= 7 u

7 u = 70

1 u = 70 ÷ 7 = 10

Number of biscuits that Jenson had at first
= 8 u
= 8 x 10
= 80 

(b)
Total number of biscuits that the 3 of them bought
= 8 u + 15 u + 5 u + 2
= 28 u + 2
= 28 x 10 + 2
= 280 + 2
= 282

Answer(s): (a) 80; (b) 282