Albert, Bryan and Fred bought some tarts. After Albert ate ²₅ of his tarts, Bryan ate ⁴₅ of his tarts and Fred ate 7 tarts, each of them had the same number of tarts left. Albert had 40 less tarts than Bryan at first.

1. How many tarts did Albert have at first?
2. How many tarts did the 3 of them buy altogether? 

	Albert	Bryan	Fred
Before	5 u	5x3 = 15 u	3 u + 7
Change	- 2 u	- 4x3 = - 12 u	- 7
After	3 u	1x3 = 3 u	3 u

(a)
The number of tarts that Albert and Bryan each had in the end is the same. Make the number of tarts that Albert and Bryan each had in the end the same.  LCM of 3 and 1 is 3.

Number of tarts that Albert had less than Bryan at first
= 15 u - 5 u
= 10 u

10 u = 40

1 u = 40 ÷ 10 = 4

Number of tarts that Albert had at first
= 5 u
= 5 x 4
= 20 

(b)
Total number of tarts that the 3 of them bought
= 5 u + 15 u + 3 u + 7
= 23 u + 7
= 23 x 4 + 7
= 92 + 7
= 99

Answer(s): (a) 20; (b) 99