Will, Flynn and Howard bought some biscuits. After Will ate ³₇ of his biscuits, Flynn ate ²₃ of his biscuits and Howard ate 9 biscuits, each of them had the same number of biscuits left. Will had 35 less biscuits than Flynn at first.

1. How many biscuits did Will have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Will	Flynn	Howard
Before	7 u	3x4 = 12 u	4 u + 9
Change	- 3 u	- 2x4 = - 8 u	- 9
After	4 u	1x4 = 4 u	4 u

(a)
The number of biscuits that Will and Flynn each had in the end is the same. Make the number of biscuits that Will and Flynn each had in the end the same.  LCM of 4 and 1 is 4.

Number of biscuits that Will had less than Flynn at first
= 12 u - 7 u
= 5 u

5 u = 35

1 u = 35 ÷ 5 = 7

Number of biscuits that Will had at first
= 7 u
= 7 x 7
= 49 

(b)
Total number of biscuits that the 3 of them bought
= 7 u + 12 u + 4 u + 9
= 23 u + 9
= 23 x 7 + 9
= 161 + 9
= 170

Answer(s): (a) 49; (b) 170