Tim, Paul and Reggie bought some tarts. After Tim ate
25 of his tarts, Paul ate
45 of his tarts and Reggie ate 9 tarts, each of them had the same number of tarts left. Tim had 90 less tarts than Paul at first.
- How many tarts did Tim have at first?
- How many tarts did the 3 of them buy altogether?
| |
Tim |
Paul |
Reggie |
Before |
5 u |
5x3 =
15 u |
3 u + 9 |
Change |
- 2 u |
- 4x3 =
- 12 u |
- 9 |
After |
3 u |
1x3 =
3 u |
3 u |
(a)
The number of tarts that Tim and Paul each had in the end is the same. Make the number of tarts that Tim and Paul each had in the end the same. LCM of 3 and 1 is 3.
Number of tarts that Tim had less than Paul at first
= 15 u - 5 u
= 10 u
10 u = 90
1 u = 90 ÷ 10 = 9
Number of tarts that Tim had at first
= 5 u
= 5 x 9
= 45
(b)
Total number of tarts that the 3 of them bought
= 5 u + 15 u + 3 u + 9
= 23 u + 9
= 23 x 9 + 9
= 207 + 9
= 216
Answer(s): (a) 45; (b) 216
