Ahmad, Tommy and Glen bought some croissants. After Ahmad ate ²₅ of his croissants, Tommy ate ²₃ of his croissants and Glen ate 7 croissants, each of them had the same number of croissants left. Ahmad had 36 less croissants than Tommy at first.

1. How many croissants did Ahmad have at first?
2. How many croissants did the 3 of them buy altogether? 

	Ahmad	Tommy	Glen
Before	5 u	3x3 = 9 u	3 u + 7
Change	- 2 u	- 2x3 = - 6 u	- 7
After	3 u	1x3 = 3 u	3 u

(a)
The number of croissants that Ahmad and Tommy each had in the end is the same. Make the number of croissants that Ahmad and Tommy each had in the end the same.  LCM of 3 and 1 is 3.

Number of croissants that Ahmad had less than Tommy at first
= 9 u - 5 u
= 4 u

4 u = 36

1 u = 36 ÷ 4 = 9

Number of croissants that Ahmad had at first
= 5 u
= 5 x 9
= 45 

(b)
Total number of croissants that the 3 of them bought
= 5 u + 9 u + 3 u + 7
= 17 u + 7
= 17 x 9 + 7
= 153 + 7
= 160

Answer(s): (a) 45; (b) 160